2 thoughts on “2.5”

    1. Right you are. Actually the numbers are correct, but I copied down the problem wrong. It should be:

      Y_p= 0.6 + 0.3 \sin(2\omega t)

      This means that the derivatives will be as such:

      \dot Y_p = 0.3 \cos(2\omega t) (2\omega)

      \ddot Y_p = -0.3 \sin(2\omega t) (2\omega)^2

      When we plug the numbers from the problem we will find those numbers that I recorded.

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