4 thoughts on “3.11”

      1. Yes, when the right hand side of the equation of motion is 0 the particular solution is also 0. This can be explained in the context of f(t) being constant as well. When the right hand side is a constant, say f(t) = h, the particular solution is

        y_p = \frac{h}{\omega_n^2}

        When h=0, y_p = 0!

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Tutoring for Statics, Dynamics, and Controls courses at Texas A&M