3.11 by Paul is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

# 3.11

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3.11 by Paul is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

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Why is the particular solution equal to zero in the second part of the problem?

Oh. Is it because for t>1 f(t) is technically equal to zero, therefore, there can be no particular solution?

Yes, when the right hand side of the equation of motion is 0 the particular solution is also 0. This can be explained in the context of being constant as well. When the right hand side is a constant, say , the particular solution is

When , !

you got me, booger.