3.12 by Paul is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

# 3.12

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3.12 by Paul is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

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for the final answer I believe it should be e^(-2.598(t-.917)) for t>.917 correct?

That is correct should appear on the last line.

why is it that you defined g(t) in mm/s^2? shouldnt it be m/s^2? 350 kg-m/s^2 / 50 kg

You are correct, the definition of g(t) should have the units of m/s^2. The unit of A stands as millimeters though.

When it says, "solve for motion for the time interval 0 < t < 1.5s," should I plug 1.5 in for t for the very bottom row of x(t)? I'm just trying to clarify that I understand the phrasing, "solve for motion."

"Solve for the motion" implies that you should find the function (in this case ) that describes the motion. Stating a position function which is valid for the entire timespan is sufficient.

This problem is the same as 3.12 in the 11th edition