## 7 thoughts on “3.12”

1. Andre Tayar says:

for the final answer I believe it should be e^(-2.598(t-.917)) for t>.917 correct?

1. tutorpaul says:

That is correct $e^{-2.598(t-0.917)}$ should appear on the last line.

2. Joseph Mascari says:

why is it that you defined g(t) in mm/s^2? shouldnt it be m/s^2? 350 kg-m/s^2 / 50 kg

1. tutorpaul says:

You are correct, the definition of g(t) should have the units of m/s^2. The unit of A stands as millimeters though.

3. blake.wallace95 says:

When it says, "solve for motion for the time interval 0 < t < 1.5s," should I plug 1.5 in for t for the very bottom row of x(t)? I'm just trying to clarify that I understand the phrasing, "solve for motion."

1. tutorpaul says:

"Solve for the motion" implies that you should find the function (in this case $x(t)$) that describes the motion. Stating a position function which is valid for the entire timespan is sufficient.

4. ledrone says:

This problem is the same as 3.12 in the 11th edition