3 thoughts on “4.26”

  1. Can you explain how even though the angular acceleration (Theta double dot) is zero, that we can assume that Phi double dot still exists? Also, why is it that we can put the made-up angle, Phi, in our final answers if Phi was not given in the original problem? I suppose we could make a relationship between Theta and Phi to make the answers in terms of Theta?

    1. As the last equations in this solution show, the angular acceleration of bar AB is dependent on the angular position, velocity, and acceleration of bar CD. To say that bar AB will not accelerate because CD didn't accelerate is a gross over-simplification of the motion of these sorts of mechanisms.

      When we think about rigid bodies we must assume that they have acceleration, velocity, and position; until we can demonstrate otherwise.

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Tutoring for Statics, Dynamics, and Controls courses at Texas A&M